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Find the value of k, if the point P (0, 2) is equidistant from (3, k) and (k, 5). |
Answer» Let the point is P(0, 2) which is equidistance from A(3, k) and B(k, 5) PA = PB \(\sqrt{(3 - 0)^2 + (k - 2)^2}\) = \(\sqrt{(k - 0)^2 + (5 - 2)^2}\) On squaring both sides, we get 9 + k2 + 4 - 4k = k2 + 9 - 4k = - 4 k = 1 |
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