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Find the value of resistance connected in a series with a bulb 60watt, 30 volt to run on 90volt supply |
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Answer» Explanation: resistance of is P = V²/ R R = V²/P = ( 30x 30)/60 = 15 ohm if applied VOLTAGE is 90v then pd across bulb is V = IR 30 = I X 15 I = 30/15 = 2A thus pd across a resistor which is connected with bulb in order to DROP only 30 v across bulb. V = I x r 60 = 2 x r r = 30OHM |
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