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Find the value of `sin^(-1) ((3)/(5)) + tan^(-1) ((1)/(7))` |
Answer» Correct Answer - `(pi)/(4)` `sin^(-1).(3)/(5) + tan^(-1).(1)/(7) = tan^(-1).(3).(4) + tan^(-1).(1)/(7)` `= tan^(-1) ((3 //4 + 1//7)/(1-3//4 xx 1//7))` `= tan^(-1) ((25)/(25)) = tan^(-1) 1 = (pi)/(4)` |
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