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Find the value of `sin^(-1)(cos(sin^(-1)x))+cos^(-1)(sin(cos^(-1)x))`A. `(pi)/(4)`B. `(pi)/(2)`C. `(3pi)/(4)`D. 0 |
Answer» We have `sin^(-1){cos(sin^(-1)x)}+cos^(-1){sin(cos^(-1)x)}` `=sin6(-1){cos((pi)/(2)cos^(-1)x)}+cos^(-1){sin(cos^(-1)x)}` `sin^(-1){sin(cos^(-1)x)}+cos^(-1){sin(cos^(-1)x)}=(pi)/(2)` |
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