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Find the value of `tan^(-1) (-tan.(13pi)/(8)) + cot^(-1) (-cot((9pi)/(8)))` |
Answer» Correct Answer - `pi` `tan^(-1) (-tan.(13pi)/(8)) + cot^(-1) (-cot ((19pi)/(8)))` `= - tan^(-1) (tan.(13pi)/(8)) + pi - cot^(-1) (cot ((19pi)/(8)))` `= -((13pi)/(8) - 2pi) + pi - ((19 pi)/(8) - 2pi)` `= (3pi)/(8) + (5pi)/(8) = pi` |
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