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Find the value of `tan^(-1)(-x)-cot^(-1)(-1/x),x gt0` |
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Answer» Since, `tan^(-1)(-x)=-tan^(-1)x` `and cot^(-1)(-1/x)=pi-cot^(-1)1/x` Also, `cot^(-1)(-1/x)=tan^(-1)x,x gt 0` `:.tan^(-1)(-x)-cot^(-1)(-1/x)` `-tan^(-1)x-(pi-cot^(-1)1/x)` `=-tan^(-1)x-pi+tan^(-1)x` `=-pi` |
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