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Find the value of the following: `cos^(-1)(cos((13pi)/6))` |
Answer» `cos^-1(cos13pi/6)` can be written as `cos^-1(cos(2pi+pi/6))` As, `cos(2pi +x) = cos x`, So, our expression becomes `=cos^-1(cos(pi/6)) = pi/6` |
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