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Find the value of x for which (8x + 4), (6x – 2) and (2x + 7) are in A.P. |
Answer» Given, (8x + 4), (6x – 2) and (2x + 7) are in A.P. So, the common difference between the consecutive terms should be the same. (6x – 2) – (8x + 4) = (2x + 7) – (6x – 2) ⇒ 6x – 2 – 8x – 4 = 2x + 7 – 6x + 2 ⇒ -2x – 6 = -4x + 9 ⇒ -2x + 4x = 9 + 6 ⇒ 2x = 15 Therefore, x = 15/2 |
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