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Find the value of x for which the numbers (5x + 2), (4x - 1) and (x + 2) are in AP. |
Answer» It is given that (5x + 2),(4x - 1) and (x + 2) are in AP. ∴ (4x - 1) - (5x + 2) = (x + 2) - (4x - 1) \(\Rightarrow\) 4x - 1 - 5x - 2 = x + 2 - 4x + 1 \(\Rightarrow\) -x - 3 = -3x + 3 \(\Rightarrow\) 3x - x = 3 + 3 \(\Rightarrow\) 2x = 6 \(\Rightarrow\) x = 3 Hence, the value of x is 3. |
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