1.

Find the value of x for which the numbers (5x + 2), (4x - 1) and (x + 2) are in AP.

Answer»

It is given that (5x + 2),(4x - 1) and (x + 2) are in AP.

∴ (4x - 1) - (5x + 2) = (x + 2) - (4x - 1)

\(\Rightarrow\) 4x - 1 - 5x - 2 = x + 2 - 4x + 1

\(\Rightarrow\) -x - 3 = -3x + 3

\(\Rightarrow\) 3x - x = 3 + 3

\(\Rightarrow\) 2x = 6

\(\Rightarrow\) x = 3

Hence, the value of x is 3.



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