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Find the value of x for which (x + 2), 2x, (2x + 3) are three consecutive terms of an AP. |
Answer» Since (x + 2), 2x and (2x + 3) are in AP, we have 2x - (x + 2) = (2x + 3) - 2x \(\Rightarrow\) x - 2 = 3 \(\Rightarrow\) x = 5 ∴ x = 5 |
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