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Find the value of x if the distance between the points (2, –11) and (x, –3) is 10 units. |
Answer» Given, \(\sqrt{(x-2)^2+(-3-(-11))^2} = 10\) ⇒ \(\sqrt{(x-2)^2+64} = 10\) ⇒ \(\sqrt{x^2-4x+4+64}=10\) ⇒ x2 – 4x + 68 = 100 ⇒ x2 – 4x – 32 = 0 ⇒ (x – 8) (x + 4) = 0 ⇒ x = 8 or – 4 |
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