1.

Find the values of k for which k + 12, k – 6 and 3 are in GP.

Answer»

To find: Value of k 

Given: k + 12, k – 6 and 3 are in GP 

Formula used: 

(i) when a,b,c are in GP b2 = ac 

As, k + 12, k – 6 and 3 are in GP 

⇒ (k – 6)2 = (k + 12) (3)

⇒ k2 – 12k + 36 = 3k + 36 

⇒ k2 – 15k = 0 

⇒ k (k – 15) = 0 

⇒ k = 0 , Or k = 15

We have two values of k as 0 or 15



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