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Find the values of k for which k + 12, k – 6 and 3 are in GP. |
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Answer» To find: Value of k Given: k + 12, k – 6 and 3 are in GP Formula used: (i) when a,b,c are in GP b2 = ac As, k + 12, k – 6 and 3 are in GP ⇒ (k – 6)2 = (k + 12) (3) ⇒ k2 – 12k + 36 = 3k + 36 ⇒ k2 – 15k = 0 ⇒ k (k – 15) = 0 ⇒ k = 0 , Or k = 15 We have two values of k as 0 or 15 |
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