1.

Find the values of tan 105°

Answer»

tan 105° = tan (60° +45°)

\(\frac{tan60°+tan45°}{1-tan60° tan 45°}\)

=\(\frac{\sqrt3+1}{1-(\sqrt3)(1)}\)

=\(\frac{\sqrt3+1}{1-\sqrt3}\)



Discussion

No Comment Found