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Find the velocity of efflux of water from an oriffice near the bottom of a tank in which pressure is `500 gf//sq` cm above atmosphere. |
Answer» Pressure at orifice, `P= 500 gf//sq cm` `= 500/1000 xx 9.8 xx (100)^(2) Nm^(-2)` `= 500 xx 9.8 Nm^(-2)` Let h be the depth of orifice below the surface. As, `P = h rho g` `:. H=P/(rho g) = (500 xx 98)/(10^(3) xx 9.8) = 5 cm` The velocity of effux, `upsilon = sqrt(2gh) = sqrt(2xx9.8xx5) = 9.893 ms^(-1)`. |
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