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find the work done by an external agent in slowly shifting a charge `q = 1 mu C` in the electric field ` vec E = 10^3 hat i Vm^-1` from the point `P(1,2) "to" Q(3, 4)`. |
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Answer» The work done by the external agent against the electric field is `W_(ext) = -q underset(1) overset(2) (int) vec E . vec d l = -qint (E hat i) .(dx hat i + dy hat j) ` = `q underset(x_1) overset(x_2)(int) E dx = q E(x_2 - x_1) = (10^-6)(10^3)(3- 1)= 2 xx 10^-3 J`. |
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