 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | Find time of flight and range of the projectile along the inclined plane as shown in figure. `(g = 10 m//s^2)` | 
| Answer» Correct Answer - A::C::D `T = (2usin(alpha +beta))/(g cos beta)` `=(2xx20sqrt(2) sin (45^@ + 30^@))/((10)cos30^@) ~~ 6.31 s` `R = u^2/(g cos^2beta) [sin(2alpha+beta) + sinbeta]` `= (20sqrt(2))^2/((10)cos^2 30^@) [sin(2xx45^@ + 30^@)+ sin30^@]` `=145.71 m` | |