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    				| 1. | Find time of flight and range of the projectile along the inclined plane as shown in figure. `(g = 10 m//s^2)` | 
| Answer» Correct Answer - A::C `T = (2usin(alpha -beta))/(g cos beta)` `((2)(20sqrt2)sin(45^@ -30^@))/((10)(cos 30^@)) = 1.69s` `R = u^2/(gcos^2beta) [sin(2alpha-beta)-sinbeta]` `=(20sqrt(2))^2/((10)cos^2 30^@) [sin(2xx45^@-30^@)- sin 30^@]` `=39m`. | |