InterviewSolution
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InterviewSolution
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Five forces ` vec A B`, ` vec A C`, ` vec A D`, ` vec A E`and ` vec A F`act at the vertex of a regular hexagon `A B C D E Fdot`Prove that the resultant is `6 vec A O`, where `O`is the centre of heaagon. |
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Answer» `vec(AB)+vec(BO)=vec(AO)` `vec(AC)+vec(CO)=vec(AO)` `vec(AD)+vec(DO)=vec(AO)` `vec(AE)+vec(EO)=vec(AD)` `vec(AF)+vec(FO)=vec(AO)` `(vec(AB)+vec(AC)+vec(AD)+vec(AB)+vec(AF))+(vec(BO)+vec(CO)+vec(DO)+vec(EO)+vec(FO))=5vec(AO)` `x+vec(AO)=5vec(AO)` `x=6vec(AO)`. |
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