1.

Prove that the sum of threevectors determined by the medians of a triangle directed from the vertices iszero.

Answer» Let `O` is the center of regular octagon `ABCDEFGH`.
Please refer to video to see the regular octagon.
Now, `vec(OA) = -vec(OE)`
`vec(OB) = -vec(OF)`
`vec(OC) = -vec(OG)`
`vec(OD) = -vec(OH)`
Now, sum of all vectors drawn from the center of this octagon
`=vec(OA)+vec(OB)+vec(OC)+vec(OD)+vec(OE)+vec(OF)+vec(OG)+vec(OH)`
`=(vec(OA)+vec(OE))+(vec(OB)+vec(OF))+(vec(OC)+vec(OG))+(vec(OD)+vec(OH))`
`=0+0+0+0 = vec0`.
Therefore, the sum of all vectors drawn from the centre of a regular octagon to its vertices is the zero vector.


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