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    				| 1. | G is a point inside the plane of the triangle `ABC, vecGA + vecGB + vecGC=0`, then show that G is the centroid of triangle ABC.A. `vec(0)`B. `3vec(GA)`C. `3 G vec(B)`D. `3 vec(GC)` | 
| Answer» Correct Answer - A We have, `G vec(B)+G vec(C ) =(1+1)vec(GD)` `rArr G vec(B) + G vec(C ) =2 vec(GD)`, where D is the mid point of BC. `rArr G vec(A) + G vec(B) + G vec(C ) =Gvec(A) +2 vec(GD) ` ` because ` G divides AD in the ratio `2 : 1 therefore 2 vec(GD) = -G vec(A)` `therefore G vec(A) +G vec(B) + G vec(C ) =G vec(A) - G vec(A) = vec(0)` | |