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InterviewSolution
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Floor of a room is of dimensions5mxx4m and it is covered with circular tiles of diameters 50 cm each as shown infigure . Find area of floor that remains uncovered with tiles. (use pi= 3.14) |
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Answer» Solution :Given, floor of a ROOM is covered with circular tiles. LENGTH of a floor of a room (l) = 5m and BREADTH of floor of a room (b) = 4m `:.` Area of floor of a room = `lxxb` = ` 5xx4= 20 m^(2)` Diameter of each circular tile = 50 cm `rArr` Redius of each circular tile = `(50)/(2)=25 cm` = `(25)/(100) m =(1)/(4)m` Now, area of a circular tile = `pi ("radius")^(2)` = ` 3.14xx((1)/(4))^(2) = (3.14)/(16)m^(2)` `:.` Area of 80 circular tiles = `80xx(3.14)/(16)= 5xx3.14 = 15.7 m^(2)` [`because` 80 congruent circular tiles covering the floor of a room] So, area of floor that remains uncovered with tiles = Area of floor of a room - Area of 80 circular tiles = `20 - 15.7 = 4.3 m^(2)` Hence, the required area of floor that remains uncovered with tiles is `4.3 m^(2)` . 
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