1.

Focus (0,-3), directrix y=3

Answer» Focus `S-=(0,-3)` and P(x,y) be a veriable point on parabola.
`:.` Now, distance of P from focus S
= perpendicular distance from P to the directrix
`rArr" "sqrt((x-0)^(2)+(y+3)^(2)-y-3)`
`rArr" "x^(2)+(y+3)^(2)=(y-3)^(2)`
`rArr=-12y`


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