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Focus (0,-3), directrix y=3 |
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Answer» Focus `S-=(0,-3)` and P(x,y) be a veriable point on parabola. `:.` Now, distance of P from focus S = perpendicular distance from P to the directrix `rArr" "sqrt((x-0)^(2)+(y+3)^(2)-y-3)` `rArr" "x^(2)+(y+3)^(2)=(y-3)^(2)` `rArr=-12y` |
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