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Focus (6,0), directrix x=-6 |
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Answer» Focus `S-=(6,0)` and directrix `x=-6" "rArr" "x+6=0` Let P(x,y) be a variable point on the parabola. `:.` Distance of from focus S = Perpendicular distance from P to the directrix. `rArrsqrt((x-6)^(2)+(y-0)^(2)=x+6)` `rArr" "(x-6)^(2)+y^(2)=(x+6)^(2)` `rArr" "y^(2)=24x` |
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