1.

Following is the graph between `log T_(50)` and `log a` (`a =` initial concentration) for a given reaction at `27^(@)C`. Hence order is A. `0`B. `1`C. `2`D. `3`

Answer» Correct Answer - A
`t_(1//2)prop((1)/(a))^(n-1) or t_(1//2)=k(a)^(1-n)`
`log.t_(1//2)=logk+(1-n)log a (y=c+mx)`
Slope `=(1-n)=tan 45=1`
`:. (1-n)=1impliesn=0`


Discussion

No Comment Found

Related InterviewSolutions