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Following is the graph between `log T_(50)` and `log a` (`a =` initial concentration) for a given reaction at `27^(@)C`. Hence order is A. `0`B. `1`C. `2`D. `3` |
Answer» Correct Answer - A `t_(1//2)prop((1)/(a))^(n-1) or t_(1//2)=k(a)^(1-n)` `log.t_(1//2)=logk+(1-n)log a (y=c+mx)` Slope `=(1-n)=tan 45=1` `:. (1-n)=1impliesn=0` |
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