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For `2NO+O_(2)to 2NO_(2)` change if the volume of the reaction vessel is doubled , the rate of the reactionA. Will diminsh to 1/4 of initial valueB. Will diminsh to 1/8 of initial valueC. Will grow 4 timesD. will grow 8 times |
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Answer» Correct Answer - B Volume is doubled therefore concentration become half . Reaction is 3d order ` therefore ((1)/(2))^(3) =(1)/(8)` |
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