1.

For a body in S.H.M. the velocity is givenby the relation V-144 -16x2 ms'. Themaximum acceleration is1) 12 m/s 2) 16m/s 3) 36m/s 4) 48m/s2 211.

Answer»

The expression of velocity in S.H.M is

V² = ω²(a² -x²) here.. a = maximum amplitude and ω is the frequency..

so, compraing V = √144-16x² = √(12)²-(4x)² , we get ω (as coefficients of x)= 4 and a as √9 = 3m

so, maximum acceleration is aω² = 3*4*4 = 48m/s²

so option D.



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