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For a Carnot engine, the source is at 500K and the sink at 300K.What is efficiency of this engine? A) 0.2 B) 0.4 C) 0.6 D) 0.3 |
Answer» Answer: B) 0.4 Explanation: Given that, T1 = 500K, T2=300 K \(\eta=\frac{T_1-T_2}{T_1}= \frac{500-300}{500}=\frac{200}{500}=0.4\) |
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