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For a certain organ pipe, three successive resonance frequencies are observer at `425`, `595` and `765 H_(Z)` respectively. Taking the speed of sound in air to be `340 m//s`, (a) explain whether the pipe is closed at one or open at boyh ends. (b) determine the fundamental frequency and length of the pipe. |
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Answer» (a) The given frequencies are the ratio `5: 7: 9`. As the frequencies are odd multiple of `85 H_(Z)`, the pipe must be closed at one end.(b) Now, the fundamebtal frequency is the lowest, i.e.`85 H_(Z)`. ltbr. :. `85 = (nu)/(4l)` rArr `l = (340)/(4 xx85) = 1m` |
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