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For a certain reaction, a plot of `([C_(0)-C])/(C )` against time `t`, yields a straight line. `C_(0)` and C are concentrations of reaction at `t=0` and `t=t` respectively. The order of reaction is:A. `3`B. ZeroC. `1`D. `2` |
Answer» Correct Answer - d For II order, `(-dC_(A))/(dt)=K[C_(A)]^(2)` On interating `1/C_(A)=Kt+ constt`., `(at t=0, C_(A)= C_(0))` `1/C=Kt+ 1/C_(0)` `((C_(0)-C))/(C_(0)-C)=Kt` or `([C_(0)-C])/C=K.C_(0).t, (y=mx+0)` |
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