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For a chemical reaction `2X+YrarrZ`, the rate of appearance of Z is 0.05 mol `L^(-1)`. The rate of disappearance of X will beA. 0.05 mol `L^(-1) min^(-1)`B. 0.05 mol `L^(-1) h^(-1)`C. 0.1 mol `L^(-1) min^(-1)`D. 0.25 mol `L^(-1) min^(-1)` |
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Answer» Correct Answer - C `2X + Y rarr Z` Hence, rate expression for the reaction will be `-(1)/(2)(d[X])/(dt)=(d[Y])/(dt)=+(d[Z])/(dt)` `therefore" "-(d[X])/(dt)=2xx0.05 " mol "L^(-1)" min"^(-1)` `=0.1 " mol "L^(-1)" min"^(-1)` |
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