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For a chemical reaction `A rarr B`, it is found that the rate of reaction doubles when the concentration of `A` is increased `4` times. What is the order of reaction ? Suggest the rate law also.A. `4`B. `0`C. `1//2`D. `1` |
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Answer» Correct Answer - C `r_(1) = k[A]^(n)` …(i) `r_(2)=2r_(1) = k[4A]^(n)` …(ii) Divide Eq. (ii) by, Eq. (i), `(2)^(1) = (4)^(n) = (2)^(2n)` `:. 2n = 1` `n = (1)/(2)`Correct Answer - C `r_(1) = k[A]^(n)` …(i) `r_(2)=2r_(1) = k[4A]^(n)` …(ii) Divide Eq. (ii) by, Eq. (i), `(2)^(1) = (4)^(n) = (2)^(2n)` `:. 2n = 1` `n = (1)/(2)` |
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