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For a chemicla reaction A`to`B, the change in concentration of A in 40s is `-0.04` mol/litre. What is the rate of chemical reaction? |
Answer» `Delta[A] = -0.004 mol L^(-1), Deltat=40s`. `therefore` Average rate of reaction = `-(Delta[A])/(Deltat)= -(-0.004 molL^(-1))/(40s) = 1.0 xx 10^(-4)mol L^(-1)s^(-1)`. |
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