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For a common emitter transistor amplifier, the audio signal voltage across the collector resistance of `2 kOmega` is 2 V. Suppose the current amplification factor of the transistor is 100, the base current if base resistance is `1 k Omega` isA. `10 muA`B. `20 muA`C. `5 muA`D. `2 muA` |
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Answer» Correct Answer - A Here, `R_C=2 kOmega =2000 Omega, R_B=1 kOmega=1000 Omega, beta=100, V_o=2V` `therefore beta=I_C/I_B=(V_o//R_C)/I_B` `therefore` Base current , `I_B=V_o/(betaR_C)=2/(100xx2000)=10^(-5) A=10 muA` |
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