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For a first-order reaction `A rarr B` the reaction rate at reactant concentration of `0.10 M` is found to be `2.0 xx 10^(-5) "mol" L^(-1) s^(-1)`. The half-life period of the reaction isA. 220sB. 30sC. 300sD. 347s |
Answer» Correct Answer - D For a first order reaction `ArarrB` , the differential rate law is Rate `=k[A]` `2.0xx10^(-5)molL^(-1)s^(-1)=k(0.01M)` `k=(2.0xx10^(-5)molL^(-1)s^(-1))/(0.01M)` `=2.0xx10^(-3)s^(-1)` For the first order reaction `t_(1//2)=(0.693)/(k)` Thus, `t_(1//2)=(0.693)/(2.0xx10^(-3)s^(-1))` `=346.5s` `=347s` |
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