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For a first order reaction half life is 14 sec. The time required for the initial concentration to reduce 1/8 of the value isA. `(14)^(3)s`B. 28sC. 42D. `(14)^(2)s` |
Answer» Correct Answer - C `N=N_(0)xx((1)/(2))^(n)` `(1)/(8)N_(0)=N_(0)xx((1)/(2))^(n)` n=3 `T=nxxt_(t//2)=3xx14=42s` |
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