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For a first order reaction , rate constant is `0.6932 "hr"^(-1)` , then half-life for the reaction isA. `0.01` hrB. 1hrC. 2hrD. 10 hr |
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Answer» Correct Answer - b `t_(1//2) = (0.693)/(k) = (0.693)/(0.6932 hr^(-1)) = 1`hr . |
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