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For a first - order reaction, the rate of reaction is `1.0xx10^(-2) mol L^(-1) s^(-1)` and the initial concentration of the reactant is 1 M. The half-life period for the reaction isA. `6.93xx10^(-3)s^(-1)`B. `0.693 s^(-1)`C. `69.3 s`D. `0.693 s^(-1)` |
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Answer» Correct Answer - C Consider a simple general first order reaction `Ararr`products Differential rate law is `Rate=k[A]` or `k=("Rate")/([A])=(1.0xx10^(-2)molL^(-1)s^(-1))/(1.0molL^(-1))` `k10^(-2)s^(-1)` For a first order reaction, half is given as `t_(1//2)=(0.693)/(10^(-2))s^(-1))` `=0.693xx10^(2)s` `=69.3s` |
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