1.

For a first order reaction velocity constant , `K = 10^(-3) s^(-1)` . Two third life for it would beA. 1100 sB. 2200 sC. 3300 sD. 4400 s

Answer» Correct Answer - a
We know that `k = (2.303)/(t)` log `(a)/(a-x)`
`10^(-3) = (2.303)/(t)` log `(a)/((a - (2a)/(3))) , 10^(-3) = (2.303)/(t)` log 3
`10^(-3) = (2.303)/(t) xx 0.4771 , t = (2.303 xx 0.4771)/(10^(-3))`
`= 1098.7` sec = 1100 sec .


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