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For a gas RCP=0.4. For this gas calculate the following (i) Atomicity and degree of freedom (ii) Value of CV and λ (iii) Mean gram- molecular kinetic energy at 300K temperature |
| Answer» GAS RCP=0.4. To find:For this gas calculate the following (i) ATOMICITY and degree of FREEDOM (ii) Value of CV and λ (iii) Mean gram- molecular kinetic energy at 300K temperatureSolution:From GIVEN, we have,A gas with R/Cp = 0.4Temperature = 300 KCp - Cv = RCp = R/0.4 = 5/2 R ⇒ Cp = 5/2 R∴ 5/2 R - Cv = R⇒ Cv = 3/2 R∴ f = 3ς = Cp/Cv= 5/2R / 3/2R∴ ς = 5/3K = 3/2RT = 3/2 R(300) ∴ K = 450R | |