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For a gaseous reaction, following data is given: `ArarrB, k_(1)= 10^(15)e-^(2000//T)``C rarrD, k_(2) = 10^(14)e^(-1000//T)` The temperature at which `k_(1) = k_(2)` isA. `1000 K`B. `2000 K`C. `868.4 K`D. `434.22 K` |
Answer» Correct Answer - d If `K_(1)=K_(2)`, then `10^(15) exp(-2000/T)=10^(14) exp(-1000/T)` or `15-2000/(Txx2.303)=14-1000/(Txx2.303)` `:. 1000/(Txx2.303) = 1` `:. T=1000/2.303=434.22` |
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