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For a gaseous reaction, following data is given: `ArarrB, k_(1)= 10^(15)e-^(2000//T)``C rarrD, k_(2) = 10^(14)e^(-1000//T)` The temperature at which `k_(1) = k_(2)` isA. `1000 K`B. `2000 K`C. `868.82 K`D. `434.2 K` |
Answer» Correct Answer - D (d) When `k_(1) = k_(2)` `10^(15)e^(-2000//T) =10^(14)e^(-1000//T)` `10= e^(1000//T) rArr ln 10 = (1000)/(T)` `rArr 2.303 log 10 = (1000)/(T)` `T = 434.2 K` |
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