1.

For a given reaction, presence of catalyst reduces the energy of activation by `2` kcal at 27^(@)C`. Thus rate of reaction will be increased by:A. `20` timesB. `14` timesC. `28` timesD. `2` times

Answer» Correct Answer - c
`K_(1)/K_(2)=e^(-[E_(a1)-E_(a2)]//RT)=e^(-[(2xx10^(3))//(2xx300)])`
`"log"_(e) K_(2)/K_(1)=(2xx10^(3))/(600)`
`K_(2)/K_(1)=28=r_(2)/r_(1)`
`:. R_(2)=28r_(1)`
`=28`


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