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For a particle moving with constant acceleration, prove that the displacement in the `n^(th)` second is given by `s_(n^(th)) = u + (a)/(2)(2n-1)` |
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Answer» From `s= ut + (1)/(2) at^(2)` `" "s_n =un + (1)/(2) an^(2) ………. (1)` `" "s_(n-1) = u(n-1) + (1)/(2) a (n-1)^(2)………. (2)` By equation (1) & (2) `s_n- s_(n-1)= s_(n^(th))= u + (a)/(2)( 2n-1)` |
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