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The velocity of a particle is given by `v=(2t^(2)-4t+3)m//s` where t is time in seconds. Find its acceleration at t=2 second.

Answer» Acceleration (a) `= (dv)/(dt) = (d)/(dt) (2 t^(2) - 4t+ 3)= 4t -4`
Therefore acceleration at `t = 2s` is equal to, `a = ( 4xx2) - 4 = 4 m//s^(2)`


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