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For a perfectly crystalline solid `C_(p.m.)=aT^(3)`, where ais constant. If `C_(p.m.)` is 0.42.J//K-"mol" at 10K, molar entropy at 10K is:A. 0.42 J/k molB. 0.14 J/K molC. 1.12 J/K molD. zero |
Answer» Correct Answer - C `0.42=a(10)^(3)impliesa=0.42xx10^(-3)` `S_(m)=int_(0)^(20)(C_(p,m))/(T)dT` `=int_(0)^(20)aT^(2)dT=(a)/(3)[20^(3)-0]` `=1.12 J//K-"mol"` |
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