1.

For a reaction A + B to C, the rate law is written as r=k[A]^(2)[B]. Doubling the concentration of 'A' without changing concentration of 'B' increases the rate of reaction by

Answer»

2 times
4 times
8 times
16 times

Solution :Since the reaction is of `2^(ND)` order with respect to A, doubling the CONCENTRATION of 'A' increases the RATE of reaction by `2^(2)=4` times.


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