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For a reaction ,`(d[X])/(d t)` is ewqual toA. `k_(1)(a-x)-k_(2)(a-x)`B. `k_(2)(a-x)-k_(1)(a-x)`C. `k_(1) (a-x)+ k_(2)(a-x)`D. `-k_(1)(a-x)-k_(2)(a-x)` |
Answer» Correct Answer - C `(-d[a-x])/(d t) = K_(1)[a-x]+K_(2)[a-x]` |
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