For a reaction of second order , `t_(75%)=xt_(50%)`. The value of X is

1.	For a reaction of second order , `t_(75%)=xt_(50%)`. The value of X is:
Answer» For the second order reaction: `t=1/k[1/[[A]]-1/[A]_(0)]` For `t_(1//2)` or `t_(50%)` `t_(50%) = 1/k[(1/[A]_(0))/2-1/[A]_(0)]=1/k[2/[A]_(0)-1/[A]_(0)]` `=1/k xx 1/[A]_(0)` For `t_(3//4)` or `t_(75%)` `t_(75%) = 1/k[(1/[A]_(0))/4-1/[A]_(0)]=1/k[4/[A]_(0)-1/[A]_(0)]=1/k xx 3/[A]_(0)` `t_(75%) = x t_(50%)` `t_(75%)/(t_(50%))=(1/k xx 3/[A]_(0))/(1/k xx 1/[A]_(0))=3` `therefore x=3`

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For a reaction of second order , `t_(75%)=xt_(50%)`. The value of X is:

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