For a reaction `pA + qB rarr` Product, the rate law expresison is `r = k[A][B]^(m)`. ThenA. `(p + 1) lt (1 + m)`B. `(p + q) gt (1 + m)`C. `(p + q)` may or may not be equal to `(1 + m)`D. `(p + q) = (1 + m)`

For a reaction `pA + qB rarr` Product, the rate law expresison is `r =

1.	For a reaction `pA + qB rarr` Product, the rate law expresison is `r = k[A][B]^(m)`. ThenA. `(p + 1) lt (1 + m)`B. `(p + q) gt (1 + m)`C. `(p + q)` may or may not be equal to `(1 + m)`D. `(p + q) = (1 + m)`
Answer» Correct Answer - C If reaction is complex, then we cannot predict order by stoichiometric coefficients and cannot justify relationship between `(p + q)` an `(l + m)`.

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For a reaction `pA + qB rarr` Product, the rate law expresison is `r = k[A][B]^(m)`. ThenA. `(p + 1) lt (1 + m)`B. `(p + q) gt (1 + m)`C. `(p + q)` may or may not be equal to `(1 + m)`D. `(p + q) = (1 + m)`

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