1.

For a reaction, the rate constant is expressed as `k = Ae^(-40000//T)`. The energy of the activation isA. `40000 cal`B. `88000 cal`C. `80000 cal`D. `8000 cal`

Answer» Correct Answer - C
`k = Ae^(-E_(a)//RT)`
`:. (-E_(a))/(R ) = -40000`
`:. E_(a) = 40000 xx 2 = 80000 cal`


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