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For a reaction, the rate constant is expressed as `k = Ae^(-40000//T)`. The energy of the activation isA. `40000 cal`B. `88000 cal`C. `80000 cal`D. `8000 cal` |
Answer» Correct Answer - C `k = Ae^(-E_(a)//RT)` `:. (-E_(a))/(R ) = -40000` `:. E_(a) = 40000 xx 2 = 80000 cal` |
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